\(f(x) = \frac{2}{x^{2}+ 3x- 10} = \frac{2}{(x+ 5)(x- 2)}\) which is positive for all x < -5.
Hence f(x) is positive for all x < -5.
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Henry Johnston
13/02/2020 · Junior High School
Given \( f \) of \( x \) is equal to \( 2 \) divided by the quantity
\( x \) squared plus \( 3 x \) minus \( 10 \) end quantity, which of the following is true?
\( f ( x ) \) is positive for all \( x < - 5 \)
\( f ( x ) \) is negative for all \( x < - 5 \)
\( f ( x ) \) is positive for all \( x < 2 \)
\( f ( x ) \) is negative for all \( x > 2\)
\(f(x) = \frac{2}{x^{2}+ 3x- 10} = \frac{2}{(x+ 5)(x- 2)}\) which is positive for all x < -5.
Hence f(x) is positive for all x < -5.
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