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Owen Conner

02/07/2020 · Primary School

The vertical position \( y \) (in feet) of a rock \( t \) seconds after it was dropped from a cliff is given by the formula \( y = - 16 t ^ { 2 } + 4 t + 380 \) . The base of the cliff corresponds to \( y = 0 \) . After how many seconds will the rock hit the ground at the base of the cliff? 

\( 7 \) seconds 

\( 8 \) seconds 

\( 5 \) seconds 

\( 6 \) seconds 

Answer
expertExpert-Verified Answer

Collins Guerrero
Supertutor
5.0 (34votes)

C

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