The initial height of the diving board is $$ 5 m $$ . The time at which Jeremiah reaches his maximum height is the $$ x $$ -coordinate of the vertex. $$x = \frac { - b } { 2 a } $$ $$ x = \frac { \square } { 2 ( \square ) } $$ $$ x = \frac { - 8 } { - 9.8 } $$ $$ x = 0.82 sec$$ It took Jeremiah $$ .82 $$ seconds to reach his maximum height. The maximum height was reached by Jeremiah at $$ \square $$ seconds. The maximum height is the $$ y $$ -coordinate of the vertex. $$h ( t ) = - 4.9 x ^ { 2 } + 8 x + 5 $$ $$ h ( 0.82 ) = - 4.9 ( 0.82 ) ^ { 2 } + 8 ( 0.82 ) + 5 $$ $$ h ( 0.82 ) = - 3.29 + 6.56 + 5 $$ $$ h ( 0.82 ) = 8.27 m$$ The maximum height reached by Jeremiah was $$ 18 m $$ .

Question

The initial height of the diving board is $$ 5 m $$ . The time at which Jeremiah reaches his maximum height is the $$ x $$ -coordinate of the vertex.  $$x = \frac { - b } { 2 a } $$ $$ x = \frac { \square } { 2 ( \square ) } $$ $$ x = \frac { - 8 } { - 9.8 } $$ $$ x = 0.82 sec$$  It took Jeremiah $$ .82 $$ seconds to reach his maximum height. The maximum height was reached by Jeremiah at $$ \square $$ seconds. The maximum height is the $$ y $$ -coordinate of the vertex. $$h ( t ) = - 4.9 x ^ { 2 } + 8 x + 5 $$ $$ h ( 0.82 ) = - 4.9 ( 0.82 ) ^ { 2 } + 8 ( 0.82 ) + 5 $$ $$ h ( 0.82 ) = - 3.29 + 6.56 + 5 $$ $$ h ( 0.82 ) = 8.27 m$$  The maximum height reached by Jeremiah was $$ 18 m $$ .

French Pearson · Accepted Answer

$$x = \frac { - b } { 2 a } $$ $$ x = \frac { - 8 } { 2 ( { - 4.9 } ) } $$ $$ x = \frac { - 8 } { - 9.8 } $$ $$ x = 0.82 sec$$  The maximum height was reached by Jeremiah at $$ 0.82 $$ seconds. The maximum height is the $$ y $$ -coordinate of the vertex.

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