Watkins Rojas
06/26/2023 · Junior High School
Question 2 (Mandatory) (1 point) An object is moving with a constant velocity of \( 5 \mathrm{~m} / \mathrm{s}[R] \), how far away is it 10 s later? \( 50 \mathrm{~m}[R] \) 50 m \( 25 \mathrm{~m}[R] \) None of the above
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Step-by-step Solution
To find out how far the object is after 10 seconds while moving at a constant velocity of \( 5 \, \text{m/s} \), you can use the formula:
\[
\text{Distance} = \text{Velocity} \times \text{Time}
\]
Substituting the given values:
\[
\text{Distance} = 5 \, \text{m/s} \times 10 \, \text{s} = 50 \, \text{m}
\]
So, the object is \( 50 \, \text{m} \) away after 10 seconds.
The correct answer is \( 50 \, \text{m} \).
Quick Answer
Distance = Velocity × Time
Distance = 5 m/s × 10 s = 50 m
The object is 50 m away after 10 seconds.
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