Black Weston
01/20/2023 · Junior High School

Solve the compound inequality. \[ 4 v+6 \leq-10 \text { or } 2 v+2<8 \] Graph the solution on the number line. If there is no solution, click on "No solutior

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Solve the equation \( 4v+6 \leq -10 \). Solve the inequality by following steps: - step0: Solve for \(v\): \(4v+6\leq -10\) - step1: Move the constant to the right side: \(4v\leq -10-6\) - step2: Subtract the numbers: \(4v\leq -16\) - step3: Divide both sides: \(\frac{4v}{4}\leq \frac{-16}{4}\) - step4: Divide the numbers: \(v\leq -4\) Solve the equation \( 2v+2 < 8 \). Solve the inequality by following steps: - step0: Solve for \(v\): \(2v+2<8\) - step1: Move the constant to the right side: \(2v<8-2\) - step2: Subtract the numbers: \(2v<6\) - step3: Divide both sides: \(\frac{2v}{2}<\frac{6}{2}\) - step4: Divide the numbers: \(v<3\) The solution to the compound inequality \(4v+6 \leq -10\) or \(2v+2 < 8\) is \(v \leq -4\) or \(v < 3\). To graph the solution on the number line, we can represent the solution as two separate intervals: \(v \leq -4\) and \(v < 3\). The solution on the number line would be a closed circle at -4 and an open circle at 3, with a line extending to the left of -4 and to the right of 3.

Quick Answer

The solution is \(v \leq -4\) or \(v < 3\). Graphically, it's a closed circle at -4 and an open circle at 3, with lines extending to the left and right.
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