Black Weston
01/20/2023 · Junior High School
Solve the compound inequality. \[ 4 v+6 \leq-10 \text { or } 2 v+2<8 \] Graph the solution on the number line. If there is no solution, click on "No solutior
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Step-by-step Solution
Solve the equation \( 4v+6 \leq -10 \).
Solve the inequality by following steps:
- step0: Solve for \(v\):
\(4v+6\leq -10\)
- step1: Move the constant to the right side:
\(4v\leq -10-6\)
- step2: Subtract the numbers:
\(4v\leq -16\)
- step3: Divide both sides:
\(\frac{4v}{4}\leq \frac{-16}{4}\)
- step4: Divide the numbers:
\(v\leq -4\)
Solve the equation \( 2v+2 < 8 \).
Solve the inequality by following steps:
- step0: Solve for \(v\):
\(2v+2<8\)
- step1: Move the constant to the right side:
\(2v<8-2\)
- step2: Subtract the numbers:
\(2v<6\)
- step3: Divide both sides:
\(\frac{2v}{2}<\frac{6}{2}\)
- step4: Divide the numbers:
\(v<3\)
The solution to the compound inequality \(4v+6 \leq -10\) or \(2v+2 < 8\) is \(v \leq -4\) or \(v < 3\).
To graph the solution on the number line, we can represent the solution as two separate intervals: \(v \leq -4\) and \(v < 3\).
The solution on the number line would be a closed circle at -4 and an open circle at 3, with a line extending to the left of -4 and to the right of 3.
Quick Answer
The solution is \(v \leq -4\) or \(v < 3\). Graphically, it's a closed circle at -4 and an open circle at 3, with lines extending to the left and right.
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