Bernard Barnett
01/02/2024 · High School
3. sebuah segi tiga \( A B C \) dengan keluasan \( 28 \mathrm{~cm}^{2} \). Diberi \( A B=9 \mathrm{~cm}, \angle A B C=34^{\circ} \) dan \( \angle B A C \) merupakan sudut terbesar dalam segl tlga \( A B C \). A triangle \( A B C \) with an area of \( 28 \mathrm{~cm}^{2} \). Given that \( A B=9 \mathrm{~cm}, \angle A B C=34^{\circ} \) and \( \angle B A C \) is the largest angle in the triangle. (a) Lakar segi tiga \( A B C \). [1 markah] [1 mark]
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Untuk melukis segi tiga \( A B C \), gunakan garis mendatar untuk sisi \( A B \) sepanjang \( 9 \, \text{cm} \), lukis sudut \( \angle A B C = 34^\circ \) dan sudut \( \angle B A C \) yang lebih besar daripada \( 34^\circ \). Gunakan formula luas segi tiga untuk menentukan panjang \( AC \).
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