Pierce Jimenez
03/31/2023 · Primary School
16. An object is launched vertically at 49 meters per second from a 980 -meter high platform. The equation for the object's height, \( h \), at time \( t \) seconds after lannch is h(t) \( =-4.9 \mathrm{r}^{2}+49 t+980 \), where \( h \) is in meters. What will be the height, in meters, of the object 6 seconds after launch?
UpStudy ThothAI Solution
Tutor-Verified Answer
Quick Answer
The height of the object 6 seconds after launch is 1097.6 meters.
Step-by-step Solution
Answered by UpStudy AI and reviewed by a Professional Tutor
UpStudy ThothAI
Self-Developed and Ever-Improving
Thoth AI product is constantly being upgraded and optimized.
Covers All Major Subjects
Capable of handling homework in math, chemistry, biology, physics, and more.
Instant and Accurate
Provides immediate and precise solutions and guidance.
Try Now
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text
Enter your question here…
By image
Re-Upload
Submit