Boone Murphy
11/08/2023 · Elementary School

NATURE OF ROOTS Without solving the equation, show that \( x^{2}+5 m x+6 m^{2}-1=0 \) has real, unequal roots for all values of \( m \).

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The discriminant \( D = m^2 + 4 \) is always greater than 0 for all values of \( m \), indicating that the equation \( x^{2} + 5mx + 6m^{2} - 1 = 0 \) has real, unequal roots for all \( m \).

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