SPORTS DRINK Your sports drink bottle is \( \frac{5}{6} \) full. After practice, the bottle is \( \frac{3}{8} \) full. Write the difference of the amounts after practice and before practice.

To find the difference between the amount of sports drink in the bottle before and after practice, we need to subtract the amount after practice from the amount before practice. Let: - The amount before practice be \( \frac{5}{6} \) - The amount after practice be \( \frac{3}{8} \) We need to calculate: \[ \frac{5}{6} - \frac{3}{8} \] To perform this subtraction, we first need a common denominator. The denominators are 6 and 8. The least common multiple (LCM) of 6 and 8 is 24. Next, we convert both fractions to have a denominator of 24: 1. For \( \frac{5}{6} \): \[ \frac{5}{6} = \frac{5 \times 4}{6 \times 4} = \frac{20}{24} \] 2. For \( \frac{3}{8} \): \[ \frac{3}{8} = \frac{3 \times 3}{8 \times 3} = \frac{9}{24} \] Now we can subtract the two fractions: \[ \frac{20}{24} - \frac{9}{24} = \frac{20 - 9}{24} = \frac{11}{24} \] Thus, the difference in the amounts of sports drink in the bottle before and after practice is: \[ \frac{11}{24} \]