Carlson Chan
03/16/2024 · Senior High School
\( \frac{3}{5} x^{4}+\frac{3}{4} x^{3} y-\frac{5}{7} x y^{3}+\frac{2}{3} y^{4} \) restar \( x^{4}+\frac{5}{8} x^{2} y^{2}-\frac{1}{3} x y^{3} \) \( +\frac{5}{6} y^{2} \)
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Step-by-step Solution
Para restar las expresiones \( \frac{3}{5} x^{4}+\frac{3}{4} x^{3} y-\frac{5}{7} x y^{3}+\frac{2}{3} y^{4} \) y \( x^{4}+\frac{5}{8} x^{2} y^{2}-\frac{1}{3} x y^{3} +\frac{5}{6} y^{2} \), primero debemos asegurarnos de que ambas expresiones estén en la misma forma.
La operación que queremos realizar es:
\[
\left( \frac{3}{5} x^{4}+\frac{3}{4} x^{3} y-\frac{5}{7} x y^{3}+\frac{2}{3} y^{4} \right) - \left( x^{4}+\frac{5}{8} x^{2} y^{2}-\frac{1}{3} x y^{3} +\frac{5}{6} y^{2} \right)
\]
Ahora, restamos cada término correspondiente:
1. Para \( x^{4} \):
\[
\frac{3}{5} x^{4} - x^{4} = \frac{3}{5} x^{4} - \frac{5}{5} x^{4} = -\frac{2}{5} x^{4}
\]
2. Para \( x^{3} y \):
\[
\frac{3}{4} x^{3} y - 0 = \frac{3}{4} x^{3} y
\]
3. Para \( x^{2} y^{2} \):
\[
0 - \frac{5}{8} x^{2} y^{2} = -\frac{5}{8} x^{2} y^{2}
\]
4. Para \( x y^{3} \):
\[
-\frac{5}{7} x y^{3} + \frac{1}{3} x y^{3} = -\frac{5}{7} x y^{3} + \frac{7}{21} x y^{3} = -\frac{15}{21} x y^{3} + \frac{7}{21} x y^{3} = -\frac{8}{21} x y^{3}
\]
5. Para \( y^{4} \):
\[
\frac{2}{3} y^{4} - \frac{5}{6} y^{2} = \frac{2}{3} y^{4} - \frac{5}{6} y^{2}
\]
Para restar estos términos, necesitamos un común denominador. El común denominador de 3 y 6 es 6:
\[
\frac{2}{3} y^{4} = \frac{4}{6} y^{4}
\]
Entonces:
\[
\frac{4}{6} y^{4} - \frac{5}{6} y^{2} = \frac{4}{6} y^{4} - \frac{5}{6} y^{2} = \frac{4y^{4} - 5y^{2}}{6}
\]
Ahora, juntamos todos los términos:
\[
-\frac{2}{5} x^{4} + \frac{3}{4} x^{3} y - \frac{5}{8} x^{2} y^{2} - \frac{8}{21} x y^{3} + \frac{4y^{4} - 5y^{2}}{6}
\]
Esta es la expresión resultante de la resta.
Quick Answer
Restar las expresiones da como resultado:
\[
-\frac{2}{5} x^{4} + \frac{3}{4} x^{3} y - \frac{5}{8} x^{2} y^{2} - \frac{8}{21} x y^{3} + \frac{4y^{4} - 5y^{2}}{6}
\]
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