Moran Simmons
08/01/2024 · Middle School

19. La solución para el siguiente binomio \( (x+2)^{3} \), es: Aplique la formula para resolver el binonio A) \( x^{3}+6 x^{2}+12 x+8 \) B) \( x^{3}+5 x^{2}+12 x+8 \) C) \( x^{3}+12 x^{2}+12 x+8 \) D) \( x^{3}+6 x^{2}+6 x+8 \)

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Para resolver el binomio \( (x+2)^{3} \), podemos utilizar la fórmula del binomio de Newton, que establece que: \[ (a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k \] En este caso, \( a = x \), \( b = 2 \) y \( n = 3 \). Entonces, aplicamos la fórmula: \[ (x + 2)^{3} = \sum_{k=0}^{3} \binom{3}{k} x^{3-k} (2)^k \] Calculamos cada término de la suma: - Para \( k = 0 \): \[ \binom{3}{0} x^{3} (2)^{0} = 1 \cdot x^{3} \cdot 1 = x^{3} \] - Para \( k = 1 \): \[ \binom{3}{1} x^{2} (2)^{1} = 3 \cdot x^{2} \cdot 2 = 6x^{2} \] - Para \( k = 2 \): \[ \binom{3}{2} x^{1} (2)^{2} = 3 \cdot x \cdot 4 = 12x \] - Para \( k = 3 \): \[ \binom{3}{3} x^{0} (2)^{3} = 1 \cdot 1 \cdot 8 = 8 \] Ahora sumamos todos los términos: \[ (x + 2)^{3} = x^{3} + 6x^{2} + 12x + 8 \] Por lo tanto, la solución es: A) \( x^{3}+6 x^{2}+12 x+8 \) La respuesta correcta es la opción **A**.

Quick Answer

La respuesta correcta es la opción A. \( x^{3}+6 x^{2}+12 x+8 \).
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