Frank Turnbull
01/12/2023 · Primary School
Find the amplitude, period, and phase shift of the function. \( y=4 \sin (3 x-\pi) \)
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Step-by-step Solution
To find the amplitude, period, and phase shift of the function \( y = 4 \sin(3x - \pi) \), we can compare it to the general form of the sine function:
\[ y = A \sin(Bx - C) \]
where:
- Amplitude = |A|
- Period = \( \frac{2\pi}{|B|} \)
- Phase Shift = \( \frac{C}{B} \)
Given function: \( y = 4 \sin(3x - \pi) \)
Comparing it to the general form:
- Amplitude = |4| = 4
- Period = \( \frac{2\pi}{|3|} = \frac{2\pi}{3} \)
- Phase Shift = \( \frac{-\pi}{3} \)
Therefore, the amplitude is 4, the period is \( \frac{2\pi}{3} \), and the phase shift is \( \frac{-\pi}{3} \).
Quick Answer
Amplitude: 4, Period: \( \frac{2\pi}{3} \), Phase Shift: \( \frac{-\pi}{3} \)
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