Vaughn Bates
03/27/2024 · Elementary School
Gegee: \( p(x)=h(x+2) \) 5.4.1 Bereken die \( x \)-afsnit van \( p \). 5.4.2 Vir watter waarde(s) van \( x \) is \( p(x)>2 \). Bepaal die \( x \)-koördinaat van punt J op \( h \) as \( 3 h(x)=726 \)
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Om die \( x \)-afsnit van \( p \) te bereken, los \( h(x + 2) = 0 \) op. Vir die waarde(s) van \( x \) waar \( p(x) > 2 \), los \( h(x + 2) > 2 \) op. Vir die \( x \)-koördinaat van punt J, los \( 3h(x) = 726 \) op en vind \( h(x) = 242 \).
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