Ross Simmons
05/25/2023 · Senior High School
What is the equation of the line through point \( (2,1) \) and perpendicular to the line through \( (-4,1) \) and \( (3,-2) ? \) \( \begin{array}{ll}\text { a) } y=\frac{7}{3} x+\frac{11}{3} & \text { go to station } 8 \\ \text { b) } y=\frac{3}{7} x+\frac{11}{3} & \text { go to station } 1 \\ \text { d) } y=-\frac{3}{7} x-\frac{11}{3} & \text { go to station } 10 \\ \text { d) } y=\frac{7}{3} x-\frac{11}{3} & \text { go to station } 5\end{array} \)
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Tutor-Verified Answer
Step-by-step Solution
To find the equation of the line through the point \( (2,1) \) that is perpendicular to the line through the points \( (-4,1) \) and \( (3,-2) \), we will follow these steps:
1. **Find the slope of the line through the points \( (-4,1) \) and \( (3,-2) \)**:
The slope \( m \) of a line through two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Substituting the points \( (-4,1) \) and \( (3,-2) \):
\[
m = \frac{-2 - 1}{3 - (-4)} = \frac{-3}{3 + 4} = \frac{-3}{7}
\]
2. **Find the slope of the line perpendicular to this line**:
The slope of a line that is perpendicular to another line is the negative reciprocal of the original slope. Therefore, if the slope of the original line is \( -\frac{3}{7} \), the slope \( m_{\perp} \) of the perpendicular line is:
\[
m_{\perp} = -\frac{1}{-\frac{3}{7}} = \frac{7}{3}
\]
3. **Use the point-slope form to find the equation of the line**:
The point-slope form of a line is given by:
\[
y - y_1 = m(x - x_1)
\]
where \( (x_1, y_1) \) is the point through which the line passes and \( m \) is the slope. Using the point \( (2,1) \) and the slope \( \frac{7}{3} \):
\[
y - 1 = \frac{7}{3}(x - 2)
\]
4. **Simplify the equation**:
Distributing the slope:
\[
y - 1 = \frac{7}{3}x - \frac{14}{3}
\]
Adding 1 (which is \( \frac{3}{3} \)) to both sides:
\[
y = \frac{7}{3}x - \frac{14}{3} + \frac{3}{3}
\]
\[
y = \frac{7}{3}x - \frac{11}{3}
\]
Thus, the equation of the line through the point \( (2,1) \) and perpendicular to the line through \( (-4,1) \) and \( (3,-2) \) is:
\[
y = \frac{7}{3}x - \frac{11}{3}
\]
The correct answer is:
**d) \( y = \frac{7}{3} x - \frac{11}{3} \)**.
Quick Answer
The equation of the line is \( y = \frac{7}{3} x - \frac{11}{3} \).
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