A ball is thrown in the air from a ledge. Its height in feet is represented by \( 1(x)=-16\left(x^{2}-5 x-6\right) \), where \( x \) is the number of seconds since the ball has been thrown. The height of the ball is 0 feet when it hits the ground. How many seconds does it take the ball to reach the ground? A. 6 B. 5 C. 1 D. 16

Solve the equation \( -16(x^{2}-5x-6)=0 \). Solve the quadratic equation by following steps: - step0: Solve by factoring: \(-16\left(x^{2}-5x-6\right)=0\) - step1: Expand the expression: \(-16x^{2}+80x+96=0\) - step2: Factor the expression: \(-16\left(x-6\right)\left(x+1\right)=0\) - step3: Divide the terms: \(\left(x-6\right)\left(x+1\right)=0\) - step4: Separate into possible cases: \(\begin{align}&x-6=0\\&x+1=0\end{align}\) - step5: Solve the equation: \(\begin{align}&x=6\\&x=-1\end{align}\) - step6: Rewrite: \(x_{1}=-1,x_{2}=6\) The solutions to the equation \( -16(x^{2}-5x-6)=0 \) are \( x=-1 \) and \( x=6 \). Since the height of the ball is 0 feet when it hits the ground, the time it takes for the ball to reach the ground is 6 seconds. Therefore, the correct answer is B. 5 seconds is incorrect, the correct answer is 6 seconds.