Simmons Reid
03/01/2023 · Elementary School
Si \( f(x)=\frac{\sqrt{3 x^{2}-8}}{2 x^{2}+6} \), entonces el valor de \( \lim _{x \rightarrow \infty} f(x) \)
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
Calculate the limit \( \lim_{x\rightarrow \infty} \frac{\sqrt{3x^2-8}}{2x^2+6} \).
Evaluate the limit by following steps:
- step0: Evaluate using transformations:
\(\lim _{x\rightarrow +\infty}\left(\frac{\sqrt{3x^{2}-8}}{2x^{2}+6}\right)\)
- step1: Rearrange the terms:
\(\lim _{x\rightarrow +\infty}\left(\frac{\sqrt{3-\frac{8}{x^{2}}}\times x}{\left(2x+\frac{6}{x}\right)x}\right)\)
- step2: Reduce the fraction:
\(\lim _{x\rightarrow +\infty}\left(\frac{\sqrt{3-\frac{8}{x^{2}}}}{2x+\frac{6}{x}}\right)\)
- step3: Rewrite the expression:
\(\frac{\lim _{x\rightarrow +\infty}\left(\sqrt{3-\frac{8}{x^{2}}}\right)}{\lim _{x\rightarrow +\infty}\left(2x+\frac{6}{x}\right)}\)
- step4: Evaluate:
\(\frac{\sqrt{3}}{\lim _{x\rightarrow +\infty}\left(2x+\frac{6}{x}\right)}\)
- step5: Evaluate:
\(\frac{\sqrt{3}}{+\infty}\)
- step6: Divide the terms:
\(0\)
El valor de \( \lim _{x \rightarrow \infty} f(x) \) es 0.
Quick Answer
El valor de \( \lim _{x \rightarrow \infty} f(x) \) es 0.
Answered by UpStudy AI and reviewed by a Professional Tutor
UpStudy ThothAI
Self-Developed and Ever-Improving
Thoth AI product is constantly being upgraded and optimized.
Covers All Major Subjects
Capable of handling homework in math, chemistry, biology, physics, and more.
Instant and Accurate
Provides immediate and precise solutions and guidance.
Try Now
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text
Enter your question here…
By image
Re-Upload
Submit