Collins Alexander
06/15/2023 · Primary School

\begin{tabular}{l} Answer the questions below about the quadratic function. \\ \( \qquad g(x)=-x^{2}-6 x-8 \) \\ Does the function have a minimum or maximum value? \\ Minimum \\ What is the function's minimum or maximum value? \\ \( \square \) \\ \( x-\square \) \\ \hline\end{tabular}

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To determine whether the quadratic function \( g(x) = -x^2 - 6x - 8 \) has a minimum or maximum value, we can analyze the coefficient of the \( x^2 \) term. Since the coefficient of \( x^2 \) is negative (specifically, -1), the parabola opens downwards, which means the function has a maximum value. Next, we can find the maximum value of the function by using the vertex formula. The x-coordinate of the vertex of a quadratic function in the form \( ax^2 + bx + c \) is given by: \[ x = -\frac{b}{2a} \] In our case, \( a = -1 \) and \( b = -6 \). Plugging in these values: \[ x = -\frac{-6}{2 \cdot -1} = \frac{6}{-2} = -3 \] Now, we can find the maximum value by substituting \( x = -3 \) back into the function \( g(x) \): \[ g(-3) = -(-3)^2 - 6(-3) - 8 \] \[ = -9 + 18 - 8 \] \[ = 1 \] Thus, the maximum value of the function is \( 1 \) at \( x = -3 \). Now we can fill in the blanks: - The function has a **maximum** value. - The function's maximum value is \( 1 \). - The value of \( x \) at which this occurs is \( -3 \). So, the completed answer is: \[ \text{Maximum} \\ \text{Maximum value: } 1 \\ x = -3 \]

Quick Answer

Maximum value: 1 at \( x = -3 \).
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