Hydrogen peroxide can be used to disinfoet and clean surfaces around the home. It breaks down over time into oxygen gas and water. The ehernieal oquation for this reaction is: 3. If 31.9 grams of oxygen was produced from 68.2 grams of hydrogen peroxide, how many grams of water would be produced? Show your work in the space below.

Given: - The molar mass of hydrogen peroxide (H₂O₂) is 34.02 g/mol. - The molar mass of oxygen (O₂) is 32.00 g/mol. - The molar mass of water (H₂O) is 18.02 g/mol. The balanced chemical equation for the decomposition of hydrogen peroxide is: \[ 2H_2O_2 \rightarrow 2H_2O + O_2 \] From the balanced equation, we can see that 2 moles of hydrogen peroxide produce 2 moles of water and 1 mole of oxygen. First, we need to calculate the number of moles of oxygen produced from 31.9 grams of oxygen: \[ \text{Moles of oxygen} = \frac{\text{Mass of oxygen}}{\text{Molar mass of oxygen}} \] \[ \text{Moles of oxygen} = \frac{31.9 \text{ g}}{32.00 \text{ g/mol}} \] Next, we can use the stoichiometry of the balanced equation to find the number of moles of water produced: \[ \text{Moles of water} = \text{Moles of oxygen} \times \frac{2 \text{ moles of water}}{1 \text{ mole of oxygen}} \] Finally, we can calculate the mass of water produced by multiplying the number of moles of water by the molar mass of water: \[ \text{Mass of water} = \text{Moles of water} \times \text{Molar mass of water} \] Let's calculate the mass of water produced. Calculate the value by following steps: - step0: Calculate: \(\frac{31.9}{32}\) - step1: Convert the expressions: \(\frac{\frac{319}{10}}{32}\) - step2: Multiply by the reciprocal: \(\frac{319}{10}\times \frac{1}{32}\) - step3: Multiply the fractions: \(\frac{319}{10\times 32}\) - step4: Multiply: \(\frac{319}{320}\) The number of moles of oxygen produced is \(0.996875\) moles. Now, let's calculate the number of moles of water produced using the stoichiometry of the balanced equation. Calculate the value by following steps: - step0: Calculate: \(0.996875\times 2\) - step1: Multiply the numbers: \(1.99375\) The number of moles of water produced is \(1.99375\) moles. Finally, let's calculate the mass of water produced by multiplying the number of moles of water by the molar mass of water. Calculate the value by following steps: - step0: Calculate: \(1.99375\times 18.02\) - step1: Multiply the numbers: \(35.927375\) The mass of water produced is approximately \(35.93\) grams. Therefore, approximately \(35.93\) grams of water would be produced from 31.9 grams of oxygen.