Create 13. Solve $$ (x-3)(x+1)(x+4)0 $$

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Create 13. Solve $$ (x-3)(x+1)(x+4)>0 $$

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$$ x \in (-4,-1) \cup (3,+\infty) $$ Solve the equation $$ (x-3)(x+1)(x+4)>0 $$. Solve the inequality by following steps: - step0: Solve the inequality by testing the values in the interval: $$\left(x-3 ight)\left(x+1 ight)\left(x+4 ight)>0$$ - step1: Rewrite the expression: $$\left(x-3 ight)\left(x+1 ight)\left(x+4 ight)=0$$ - step2: Separate into possible cases: $$\begin{align}&x-3=0\&x+1=0\&x+4=0\end{align}$$ - step3: Solve the equation: $$\begin{align}&x=3\&x=-1\&x=-4\end{align}$$ - step4: Determine the test intervals: $$\begin{align}&x<-4\&-43\end{align}$$ - step5: Choose a value: $$\begin{align}&x_{1}=-5\&x_{2}=-3\&x_{3}=1\&x_{4}=4\end{align}$$ - step6: Test the chosen value: $$\begin{align}&x<-4 extrm{ } extrm{is not a solution}\&-43 extrm{ } extrm{is the solution}\end{align}$$ - step7: The final solution is $$x \in \left(-4,-1 ight)\cup \left(3,+\infty ight):$$ $$x \in \left(-4,-1 ight)\cup \left(3,+\infty ight)$$ The solution to the inequality $$ (x-3)(x+1)(x+4)>0 $$ is $$ x \in (-4,-1) \cup (3,+\infty) $$.

Create 13. Solve \( (x-3)(x+1)(x+4)>0 \)

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Create 13. Solve \( (x-3)(x+1)(x+4)>0 \)

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