Which of the following statements is true if \( \lim _{x \rightarrow 3} f(x)=5 \) and \( f(3)=4 \) ? \( f(x) \) is continuous at \( x=3 \) \( f(x) \) is discontinuous at \( x=3 \) \( f(x) \) has a linit at infinity The linit does not evist at \( x=3 \)

A \( \sqrt[3]{-8} \) B \( \sqrt[4]{-16} \) C \( \sqrt[3]{64} \) D \( \sqrt[4]{16} \) \( 1.2 \quad \) The LCM and HCF of 16,24 and 36 is A \( \quad \) LCM \( =144 \) and HCF \( =4 \) B \( \quad \) LCM \( =4 \) and HCF \( =144 \) C \( \quad \) LCM \( =48 \) and HCF \( =12 \) D \( \quad \) LCM \( =16 \) and HCF \( =2 \)

2. \( { }^{1}+2= \)

Solve for \( v \). \[ v^{2}+4 v-21=0 \] If there is more than one solution, separate them with commas. If there is no solution, click on "No solution."

CREA \( \rightarrow \) Plantea una tabla de valores para relacionar las magnitudes en cada caso. Luego, realiza la representación gráfica. a. La longitud del lado de un cuadrado y su perímetro.

5. Rechne aus. Du kannst Stellenwertkarten oder eine Stellenwerttabelle benutzen. \( \begin{array}{ll}\text { a } 0.975-0.9= & \text { b } 0.468-0.4= \\ 0.975-0.07= & 0.468-0.06= \\ 0.975-0.005= & 0.468-0.008= \\ \text { c } 14.441-0.4= & \text { d } 111.111-10 \\ 14.441-0.04= & 111.111-0.1= \\ 14.441-0.001= & 111.111-0.001=\end{array} \)