Griffin Ruiz
02/06/2023 · High School
Dada la siguiente curva en coordenadas rectangulares \[ \left(x^{2}+y^{2}-6 x\right)^{2}=4 x^{2}+4 y^{2} \] i) Transforme la curva a coordenadas polares.
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Para transformar la curva en coordenadas rectangulares a coordenadas polares, sustituimos \(x\) por \(r \cos(\theta)\) y \(y\) por \(r \sin(\theta)\). Luego simplificamos y obtenemos la ecuación en coordenadas polares: \(r^2 - 12r \cos(\theta) + (36 \cos^2(\theta) - 4) = 0\).
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