\( m _ { sec } = \frac { y - ( - 2,5 ) } { x - 1.5 } = \)

The expression you've provided seems to represent the slope of a line in the form of the slope-intercept equation or the point-slope form of a line. The notation \( m_{sec} \) typically refers to the slope of a secant line between two points. The expression can be interpreted as follows: \[ m_{sec} = \frac{y - (-2.5)}{x - 1.5} \] This can be simplified to: \[ m_{sec} = \frac{y + 2.5}{x - 1.5} \] In this context, \( (1.5, -2.5) \) appears to be a point on the line, and \( (x, y) \) represents another point on the line. The slope \( m_{sec} \) measures the rate of change of \( y \) with respect to \( x \) between these two points. If you have specific values for \( x \) and \( y \), you can substitute them into the equation to find the slope. If you need further assistance or clarification, please provide more context or details!