$$ 9 ( n ) 2 ^ { n - 1 } \cup [ n ] $$

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The expression represents the union of a set generated by the function $$ 9 \cdot n \cdot 2^{n-1} $$ and the set of the first $$ n $$ natural numbers. It seems like you're presenting a mathematical expression or notation that involves a union of two sets. However, the notation is a bit unclear. Let's break it down: 1. **$$ 9(n)2^{n-1} $$**: This part is not standard notation. It could potentially represent a function or a sequence, but without additional context, it's hard to interpret. If $$ 9(n) $$ is meant to indicate a function of $$ n $$, it might be clearer if written as $$ 9 \cdot n \cdot 2^{n-1} $$ or something similar. 2. **$$ [n] $$**: This typically denotes the set of the first $$ n $$ natural numbers, i.e., $$ \{1, 2, 3, \ldots, n\} $$. 3. **Union $$ \cup $$**: The union operator indicates that we are combining two sets. If we assume that $$ 9(n)2^{n-1} $$ is meant to represent a set of numbers generated by some function of $$ n $$, then the expression could be interpreted as the union of that set with the set of the first $$ n $$ natural numbers. To clarify, if we denote the first part as a set $$ A = \{ 9 \cdot n \cdot 2^{n-1} \} $$ (assuming it generates a single value for a specific $$ n $$), and the second part as $$ B = [n] = \{1, 2, \ldots, n\} $$, then the expression would represent: $$ A \cup B = \{ 9 \cdot n \cdot 2^{n-1} \} \cup \{1, 2, \ldots, n\} $$ If you can provide more context or clarify the notation, I would be happy to help further!

\( 9 ( n ) 2 ^ { n - 1 } \cup [ n ] \)

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\( 9 ( n ) 2 ^ { n - 1 } \cup [ n ] \)

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