Step-by-step Solution
Oto wyniki dodawania dla podanych ułamków:
(f) \( 4 \frac{1}{2} + 3 \frac{4}{5} = 7 \frac{3}{10} \)
(g) \( 6 \frac{2}{3} + 4 \frac{8}{9} = 11 \frac{1}{9} \)
(h) \( 4 \frac{5}{6} + 3 \frac{1}{3} = 8 \frac{1}{2} \)
(i) \( 4 \frac{3}{8} + 6 \frac{3}{4} = 11 \frac{5}{8} \)
(j) \( 6 \frac{1}{2} + 4 \frac{3}{10} = 10 \frac{1}{5} \)
(k) \( 2 \frac{5}{9} + 3 \frac{2}{3} = 6 \frac{1}{9} \)
(l) \( 6 \frac{7}{10} + 4 \frac{3}{5} = 11 \frac{1}{10} \)
(m) \( 4 \frac{11}{12} + 2 \frac{2}{3} = 7 \frac{3}{4} \)
(n) \( 5 \frac{7}{9} + 2 \frac{2}{3} = 8 \frac{1}{9} \)
(o) \( 2 \frac{4}{5} + 4 \frac{7}{10} = 7 \frac{3}{10} \)
(p) \( 2 \frac{1}{4} + 2 \frac{1}{5} = 4 \frac{9}{20} \)
(q) \( 5 \frac{1}{2} + 3 \frac{4}{7} = 8 \frac{1}{14} \)
(r) \( 6 \frac{2}{3} + 4 \frac{3}{5} = 11 \frac{1}{15} \)
(s) \( 3 \frac{3}{4} + 4 \frac{4}{5} = 8 \frac{7}{20} \)
(t) \( 7 \frac{3}{8} + 4 \frac{1}{3} = 11 \frac{5}{24} \)
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Quick Answer
(f) \( 4 \frac{1}{2} + 3 \frac{4}{5} = 7 \frac{3}{10} \)
(g) \( 6 \frac{2}{3} + 4 \frac{8}{9} = 11 \frac{1}{9} \)
(h) \( 4 \frac{5}{6} + 3 \frac{1}{3} = 8 \frac{1}{2} \)
(i) \( 4 \frac{3}{8} + 6 \frac{3}{4} = 11 \frac{5}{8} \)
(j) \( 6 \frac{1}{2} + 4 \frac{3}{10} = 10 \frac{1}{5} \)
(k) \( 2 \frac{5}{9} + 3 \frac{2}{3} = 6 \frac{1}{9} \)
(l) \( 6 \frac{7}{10} + 4 \frac{3}{5} = 11 \frac{1}{10} \)
(m) \( 4 \frac{11}{12} + 2 \frac{2}{3} = 7 \frac{3}{4} \)
(n) \( 5 \frac{7}{9} + 2 \frac{2}{3} = 8 \frac{1}{9} \)
(o) \( 2 \frac{4}{5} + 4 \frac{7}{10} = 7 \frac{3}{10} \)
(p) \( 2 \frac{1}{4} + 2 \frac{1}{5} = 4 \frac{9}{20} \)
(q) \( 5 \frac{1}{2} + 3 \frac{4}{7} = 8 \frac{1}{14} \)
(r) \( 6 \frac{2}{3} + 4 \frac{3}{5} = 11 \frac{1}{15} \)
(s) \( 3 \frac{3}{4} + 4 \frac{4}{5} = 8 \frac{7}{20} \)
(t) \( 7 \frac{3}{8} + 4 \frac{1}{3} = 11 \frac{5}{24} \)
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