Maxwell Johnston
03/24/2023 · Middle School
10. Quadrilateral \( A B C D \) with vertices \( A(2,5) \). \( B(5,8), C(8,-1) \), and \( D(1,1) \) : (a) Translation: \( (x, y) \rightarrow(x-9, y-4) \) (b) Reflection: in the \( y \)-axis
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Step-by-step Solution
To perform the transformations on the quadrilateral \( ABCD \) with vertices \( A(2,5) \), \( B(5,8) \), \( C(8,-1) \), and \( D(1,1) \), we will follow the steps for each transformation.
### (a) Translation: \( (x, y) \rightarrow (x-9, y-4) \)
For the translation, we will subtract 9 from the x-coordinates and 4 from the y-coordinates of each vertex.
1. **Vertex A**:
\[
A(2, 5) \rightarrow A'(2-9, 5-4) = A'(-7, 1)
\]
2. **Vertex B**:
\[
B(5, 8) \rightarrow B'(5-9, 8-4) = B'(-4, 4)
\]
3. **Vertex C**:
\[
C(8, -1) \rightarrow C'(8-9, -1-4) = C'(-1, -5)
\]
4. **Vertex D**:
\[
D(1, 1) \rightarrow D'(1-9, 1-4) = D'(-8, -3)
\]
After the translation, the new vertices are:
- \( A'(-7, 1) \)
- \( B'(-4, 4) \)
- \( C'(-1, -5) \)
- \( D'(-8, -3) \)
### (b) Reflection: in the \( y \)-axis
For the reflection in the \( y \)-axis, we will change the sign of the x-coordinates of each vertex while keeping the y-coordinates the same.
1. **Vertex A'**:
\[
A'(-7, 1) \rightarrow A''(7, 1)
\]
2. **Vertex B'**:
\[
B'(-4, 4) \rightarrow B''(4, 4)
\]
3. **Vertex C'**:
\[
C'(-1, -5) \rightarrow C''(1, -5)
\]
4. **Vertex D'**:
\[
D'(-8, -3) \rightarrow D''(8, -3)
\]
After the reflection in the \( y \)-axis, the new vertices are:
- \( A''(7, 1) \)
- \( B''(4, 4) \)
- \( C''(1, -5) \)
- \( D''(8, -3) \)
### Summary of Results
- After translation:
- \( A'(-7, 1) \)
- \( B'(-4, 4) \)
- \( C'(-1, -5) \)
- \( D'(-8, -3) \)
- After reflection in the \( y \)-axis:
- \( A''(7, 1) \)
- \( B''(4, 4) \)
- \( C''(1, -5) \)
- \( D''(8, -3) \)
Quick Answer
After translation: \( A'(-7, 1) \), \( B'(-4, 4) \), \( C'(-1, -5) \), \( D'(-8, -3) \)
After reflection in the \( y \)-axis: \( A''(7, 1) \), \( B''(4, 4) \), \( C''(1, -5) \), \( D''(8, -3) \)
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