Brewer Clark
01/05/2024 · Junior High School
Si al sistema: \( x-y=1 \) \( y+z=2 \) le añadimos la ecuación \( \dot{x}+z=3 \), entonces el sistema resultante es Compatible determinado Compatible indeterminado incompatible Compatible
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Para determinar si el sistema resultante es compatible, determinado, indeterminado o incompatible, necesitamos resolver el sistema de ecuaciones.
Dado que el sistema original es:
1. \( x - y = 1 \)
2. \( y + z = 2 \)
3. \( \dot{x} + z = 3 \)
Podemos resolver el sistema de ecuaciones de la siguiente manera:
1. Sumar la primera ecuación con la tercera ecuación para eliminar la variable \( y \):
\( (x - y) + (\dot{x} + z) = 1 + 3 \)
\( x + \dot{x} + z - y = 4 \)
2. Restar la segunda ecuación de la ecuación resultante para eliminar la variable \( z \):
\( (x + \dot{x} + z - y) - (y + z) = 4 - 2 \)
\( x + \dot{x} - 2y = 2 \)
3. Ahora tenemos un sistema de dos ecuaciones con dos variables:
1. \( x - y = 1 \)
2. \( x + \dot{x} - 2y = 2 \)
Podemos resolver este sistema de ecuaciones para determinar si es compatible, determinado, indeterminado o incompatible.
Solve the system of equations by following steps:
- step0: Solve using the substitution method:
\(\left\{ \begin{array}{l}x-y=1\\x-2y=2\end{array}\right.\)
- step1: Solve the equation:
\(\left\{ \begin{array}{l}x=1+y\\x-2y=2\end{array}\right.\)
- step2: Substitute the value of \(x:\)
\(1+y-2y=2\)
- step3: Subtract the terms:
\(1-y=2\)
- step4: Move the constant to the right side:
\(-y=2-1\)
- step5: Subtract the numbers:
\(-y=1\)
- step6: Change the signs:
\(y=-1\)
- step7: Substitute the value of \(y:\)
\(x=1-1\)
- step8: Simplify:
\(x=0\)
- step9: Calculate:
\(\left\{ \begin{array}{l}x=0\\y=-1\end{array}\right.\)
- step10: Check the solution:
\(\left\{ \begin{array}{l}x=0\\y=-1\end{array}\right.\)
- step11: Rewrite:
\(\left(x,y\right) = \left(0,-1\right)\)
El sistema de ecuaciones es compatible y tiene una solución única, por lo tanto, el sistema resultante es determinado.
Quick Answer
El sistema resultante es determinado.
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