A chalkboard measures 8 feet by 4 feet. How many square feet of area is available for writing? $$ \begin{array}{llllll} ext { A. } 12 \mathrm{ft}^{2} & ext { B. } 24 \mathrm{ft}^{2} & ext { C. } 32 \mathrm{ft}^{2} & ext { D. } 36 \mathrm{ft}^{2}\end{array} $$

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A chalkboard measures 8 feet by 4 feet. How many square feet of area is available for writing? $$ \begin{array}{llllll}	ext { A. } 12 \mathrm{ft}^{2} & 	ext { B. } 24 \mathrm{ft}^{2} & 	ext { C. } 32 \mathrm{ft}^{2} & 	ext { D. } 36 \mathrm{ft}^{2}\end{array} $$

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The area available for writing is 32 square feet. Therefore, the correct answer is C. 32 ft². To find the area of the chalkboard, you can use the formula for the area of a rectangle, which is: $$ \text{Area} = \text{length} \times \text{width} $$ In this case, the length is 8 feet and the width is 4 feet. Plugging in these values: $$ \text{Area} = 8 \, \text{ft} \times 4 \, \text{ft} = 32 \, \text{ft}^2 $$ Therefore, the area available for writing on the chalkboard is $$ \boxed{32} \, \text{ft}^2 $$.

A chalkboard measures 8 feet by 4 feet. How many square feet of area is available for writing? \( \begin{array}{llllll}\text { A. } 12 \mathrm{ft}^{2} & \text { B. } 24 \mathrm{ft}^{2} & \text { C. } 32 \mathrm{ft}^{2} & \text { D. } 36 \mathrm{ft}^{2}\end{array} \)

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A chalkboard measures 8 feet by 4 feet. How many square feet of area is available for writing? \( \begin{array}{llllll}\text { A. } 12 \mathrm{ft}^{2} & \text { B. } 24 \mathrm{ft}^{2} & \text { C. } 32 \mathrm{ft}^{2} & \text { D. } 36 \mathrm{ft}^{2}\end{array} \)

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