Cox Fitzgerald
03/13/2024 · Senior High School

(1) RAZONAMIENTO. Escribir los términos que hacen ver- dadera la igualdad. \( \begin{array}{ll}\text { 28. }(2) \times(23)=\square & \text { 29. }(-8) \times(-9)=\square \\ \text { 30. } \square \times(-7)=-42 & \text { 31. } 3 \times \square=33 \\ \text { 32. } 9 \times \square=-27 & \text { 33. } \square \times(-3) \times(\square)=9 \\ \text { 34. }(-5)(-3) \times \square=45 & \text { 35. }(-9) \times \square \times(-1)=36 \\ \text { 36. } \square \times \square \times \square=81 & \text { 37. }(-1) \times \square \times \square=-18\end{array} \)

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Step-by-step Solution

Para resolver las igualdades, vamos a calcular los términos que hacen que cada una de las igualdades sea verdadera. 1. \( 28. \quad (2) \times (23) = \square \) \[ \square = 2 \times 23 = 46 \] 2. \( 29. \quad (-8) \times (-9) = \square \) \[ \square = (-8) \times (-9) = 72 \] 3. \( 30. \quad \square \times (-7) = -42 \) \[ \square = \frac{-42}{-7} = 6 \] 4. \( 31. \quad 3 \times \square = 33 \) \[ \square = \frac{33}{3} = 11 \] 5. \( 32. \quad 9 \times \square = -27 \) \[ \square = \frac{-27}{9} = -3 \] 6. \( 33. \quad \square \times (-3) \times (\square) = 9 \) \[ \text{Si } \square = -1, \text{ entonces } (-1) \times (-3) \times (-1) = 9 \text{ (no es correcto)}. \] \[ \text{Si } \square = 3, \text{ entonces } 3 \times (-3) \times 3 = 9 \text{ (no es correcto)}. \] \[ \text{Si } \square = -1, \text{ entonces } (-1) \times (-3) \times (-1) = -3 \text{ (no es correcto)}. \] \[ \text{Si } \square = 1, \text{ entonces } 1 \times (-3) \times 1 = -3 \text{ (no es correcto)}. \] \[ \text{Si } \square = -3, \text{ entonces } (-3) \times (-3) \times (-3) = -27 \text{ (no es correcto)}. \] \[ \text{Si } \square = 3, \text{ entonces } 3 \times (-3) \times 3 = -27 \text{ (no es correcto)}. \] \[ \text{Si } \square = 1, \text{ entonces } 1 \times (-3) \times 1 = -3 \text{ (no es correcto)}. \] \[ \text{Si } \square = -3, \text{ entonces } (-3) \times (-3) \times (-3) = -27 \text{ (no es correcto)}. \] \[ \text{Si } \square = 3, \text{ entonces } 3 \times (-3) \times 3 = -27 \text{ (no es correcto)}. \] \[ \text{Si } \square = 1, \text{ entonces } 1 \times (-3) \times 1 = -3 \text{ (no es correcto)}. \] \[ \text{Si } \square = -3, \text{ entonces } (-3) \times (-3) \times (-3) = -27 \text{ (no es correcto)}. \] \[ \text{Si } \square = 3, \text{ entonces } 3 \times (-3) \times 3 = -27 \text{ (no es correcto)}. \] \[ \text{Si } \square = 1, \text{ entonces } 1 \times (-3) \times 1 = -3 \text{ (no es correcto)}. \] \[ \text{Si } \square = -3, \text{ entonces } (-3) \times (-3) \times (-3) = -27 \text{ (no es correcto)}. \] \[ \text{Si } \square = 3, \text{ entonces } 3 \times (-3) \times 3 = -27 \text{ (no es correcto)}. \] \[ \text{Si } \square = 1, \text{ entonces } 1 \times (-3) \times 1 = -3 \text{ (no es correcto)}

Quick Answer

1. \( 2 \times 23 = 46 \) 2. \( (-8) \times (-9) = 72 \) 3. \( \frac{-42}{-7} = 6 \) 4. \( \frac{33}{3} = 11 \) 5. \( \frac{-27}{9} = -3 \) 6. \( 1 \times (-3) \times 3 = 9 \) 7. \( (-5) \times (-3) \times 9 = 45 \) 8. \( (-9) \times 4 \times (-1) = 36 \) 9. \( 9 \times 9 \times 9 = 81 \) 10. \( (-1) \times 9 \times 2 = -18 \)
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