Leo has \( \$(x+6) \) and Sue has \( \$\left(x^{2}+2 x-3\right) \). a. How much do the children have? b. If \( x \) is 5 , what is the amount?

To solve the problem, we will first find the total amount of money that Leo and Sue have, and then we will calculate the amounts when \( x = 5 \). ### Part a: Total Amount 1. **Leo's Amount**: \[ \text{Leo's amount} = x + 6 \] 2. **Sue's Amount**: \[ \text{Sue's amount} = x^2 + 2x - 3 \] 3. **Total Amount**: To find the total amount of money that both children have, we add Leo's and Sue's amounts together: \[ \text{Total amount} = (x + 6) + (x^2 + 2x - 3) \] Now, combine like terms: \[ \text{Total amount} = x^2 + 2x + x + 6 - 3 \] \[ \text{Total amount} = x^2 + 3x + 3 \] ### Part b: Amount when \( x = 5 \) Now, we will substitute \( x = 5 \) into the total amount expression: \[ \text{Total amount} = 5^2 + 3(5) + 3 \] Calculating each term: \[ 5^2 = 25 \] \[ 3(5) = 15 \] Now, add these values together: \[ \text{Total amount} = 25 + 15 + 3 = 43 \] ### Final Answers a. The total amount of money that Leo and Sue have is \( x^2 + 3x + 3 \). b. If \( x = 5 \), the total amount is \( \$43 \).