Reyes Carter
07/15/2024 · Junior High School
Factorise \( 6 a+24 b+3 \) \( =\square a+\square b+\square \) Please fill in all the gaps.
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
To factorise the expression \( 6a + 24b + 3 \), we can look for a common factor in all the terms.
1. The coefficients of \( a \), \( b \), and the constant term are \( 6 \), \( 24 \), and \( 3 \) respectively. The greatest common divisor (GCD) of these numbers is \( 3 \).
2. We can factor out \( 3 \) from the expression:
\[
6a + 24b + 3 = 3(2a + 8b + 1)
\]
Now, we can express the factored form in the required format:
\[
= \square a + \square b + \square
\]
From the factored expression \( 3(2a + 8b + 1) \), we can identify:
- The coefficient of \( a \) is \( 2 \) (so \( \square = 2 \)),
- The coefficient of \( b \) is \( 8 \) (so \( \square = 8 \)),
- The constant term is \( 1 \) (so \( \square = 1 \)).
Thus, we can fill in the gaps as follows:
\[
= 2a + 8b + 1
\]
So the final answer is:
\[
6a + 24b + 3 = 2a + 8b + 1
\]
The filled gaps are \( 2 \), \( 8 \), and \( 1 \).
Quick Answer
\( 6a + 24b + 3 = 2a + 8b + 1 \)
The filled gaps are \( 2 \), \( 8 \), and \( 1 \).
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