Find the center and radius of the circle. \[ (x+3)^{2}+(y-4)^{2}=26 \] The center of the circle is (Type an ordered pair.)

The equation of the circle is given in the standard form: \[ (x - h)^2 + (y - k)^2 = r^2 \] where \((h, k)\) is the center of the circle and \(r\) is the radius. In your equation: \[ (x + 3)^2 + (y - 4)^2 = 26 \] we can rewrite it to match the standard form: \[ (x - (-3))^2 + (y - 4)^2 = 26 \] From this, we can identify: - The center \((h, k)\) is \((-3, 4)\). - The radius \(r\) can be found by taking the square root of 26: \[ r = \sqrt{26} \] Thus, the center of the circle is: \[ \boxed{(-3, 4)} \]