Find the center and radius of the circle. $$ x^{2}+(y-8)^{2}=64 $$ The center of the circle is (Type an ordered pair.)

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The center of the circle is $$(0, 8)$$. The equation of the circle is given as $$ x^{2} + (y - 8)^{2} = 64. $$ This equation is in the standard form of a circle, which is $$ (x - h)^{2} + (y - k)^{2} = r^{2}, $$ where $$(h, k)$$ is the center of the circle and $$r$$ is the radius. From the given equation, we can identify the following: - The term $$x^{2}$$ indicates that $$h = 0$$ (since there is no $$(x - h)$$ term). - The term $$(y - 8)^{2}$$ indicates that $$k = 8$$. - The right side of the equation, $$64$$, represents $$r^{2}$$. Therefore, $$r = \sqrt{64} = 8$$. Thus, the center of the circle is $$ (0, 8) $$ and the radius is $$ 8. $$ So, the center of the circle is $$ \boxed{(0, 8)}. $$

Find the center and radius of the circle. \[ x^{2}+(y-8)^{2}=64 \] The center of the circle is (Type an ordered pair.)

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Find the center and radius of the circle. \[ x^{2}+(y-8)^{2}=64 \] The center of the circle is (Type an ordered pair.)

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