Bryant Fowler
05/05/2023 · Primary School
Find the intercepts of the circle. \[ (x+4)^{2}+(y+3)^{2}=49 \] Select the correct choice below and, if necessary, fill in the answer box within your choice. A. The \( x \)-intercept(s) is/are (Use a comma to separate answers as needed. Type an exact answer, using radicals as needed.) There is no x-intercept.
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Step-by-step Solution
To find the intercepts of the circle given by the equation
\[
(x+4)^{2}+(y+3)^{2}=49,
\]
we will first identify the center and radius of the circle. The equation is in the standard form \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius.
From the equation, we can see that:
- The center \((h, k)\) is \((-4, -3)\).
- The radius \(r\) is \(\sqrt{49} = 7\).
### Finding the \(x\)-intercepts
To find the \(x\)-intercepts, we set \(y = 0\) and solve for \(x\):
\[
(x + 4)^2 + (0 + 3)^2 = 49.
\]
This simplifies to:
\[
(x + 4)^2 + 3^2 = 49,
\]
\[
(x + 4)^2 + 9 = 49.
\]
Subtracting 9 from both sides gives:
\[
(x + 4)^2 = 40.
\]
Taking the square root of both sides, we have:
\[
x + 4 = \pm \sqrt{40}.
\]
Since \(\sqrt{40} = \sqrt{4 \cdot 10} = 2\sqrt{10}\), we can write:
\[
x + 4 = 2\sqrt{10} \quad \text{or} \quad x + 4 = -2\sqrt{10}.
\]
Solving for \(x\):
1. \(x + 4 = 2\sqrt{10} \Rightarrow x = 2\sqrt{10} - 4\)
2. \(x + 4 = -2\sqrt{10} \Rightarrow x = -2\sqrt{10} - 4\)
Thus, the \(x\)-intercepts are:
\[
x = 2\sqrt{10} - 4, \quad x = -2\sqrt{10} - 4.
\]
### Finding the \(y\)-intercepts
To find the \(y\)-intercepts, we set \(x = 0\) and solve for \(y\):
\[
(0 + 4)^2 + (y + 3)^2 = 49.
\]
This simplifies to:
\[
4^2 + (y + 3)^2 = 49,
\]
\[
16 + (y + 3)^2 = 49.
\]
Subtracting 16 from both sides gives:
\[
(y + 3)^2 = 33.
\]
Taking the square root of both sides, we have:
\[
y + 3 = \pm \sqrt{33}.
\]
Solving for \(y\):
1. \(y + 3 = \sqrt{33} \Rightarrow y = \sqrt{33} - 3\)
2. \(y + 3 = -\sqrt{33} \Rightarrow y = -\sqrt{33} - 3\)
Thus, the \(y\)-intercepts are:
\[
y = \sqrt{33} - 3, \quad y = -\sqrt{33} - 3.
\]
### Summary of Intercepts
- The \(x\)-intercepts are \(2\sqrt{10} - 4, -2\sqrt{10} - 4\).
- The \(y\)-intercepts are \(\sqrt{33} - 3, -\sqrt{33} - 3\).
### Final Answer
A. The \(x\)-intercept(s) is/are:
\[
2\sqrt{10} - 4, -2\sqrt{10} - 4.
\]
Quick Answer
The \(x\)-intercepts are \(2\sqrt{10} - 4\) and \(-2\sqrt{10} - 4\).
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