Reyes Chavez
11/11/2023 · Senior High School
Section 14.4 Given a mean, standard deviation, and a raw score, find the corresponding z-score. Assume the distribution is normal. Mean 70 , standard deviation \( 8.1, x=90 \) What is the corresponding \( z \)-score? \( 0 \%, 0 \) of 36 ; \( z=\square \) (Round to two decimal places as needed.)
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Tutor-Verified Answer
Step-by-step Solution
To find the corresponding z-score for a given raw score \( x \), you can use the formula:
\[
z = \frac{x - \mu}{\sigma}
\]
where:
- \( x \) is the raw score,
- \( \mu \) is the mean,
- \( \sigma \) is the standard deviation.
Given:
- Mean \( \mu = 70 \)
- Standard deviation \( \sigma = 8.1 \)
- Raw score \( x = 90 \)
Now, plug in the values into the formula:
\[
z = \frac{90 - 70}{8.1}
\]
Calculating the numerator:
\[
90 - 70 = 20
\]
Now, divide by the standard deviation:
\[
z = \frac{20}{8.1} \approx 2.4691358
\]
Rounding to two decimal places:
\[
z \approx 2.47
\]
Thus, the corresponding z-score is:
\[
z = 2.47
\]
Quick Answer
The corresponding z-score is 2.47.
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