Reyes Chavez
11/11/2023 · Senior High School

Section 14.4 Given a mean, standard deviation, and a raw score, find the corresponding z-score. Assume the distribution is normal. Mean 70 , standard deviation \( 8.1, x=90 \) What is the corresponding \( z \)-score? \( 0 \%, 0 \) of 36 ; \( z=\square \) (Round to two decimal places as needed.)

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To find the corresponding z-score for a given raw score \( x \), you can use the formula: \[ z = \frac{x - \mu}{\sigma} \] where: - \( x \) is the raw score, - \( \mu \) is the mean, - \( \sigma \) is the standard deviation. Given: - Mean \( \mu = 70 \) - Standard deviation \( \sigma = 8.1 \) - Raw score \( x = 90 \) Now, plug in the values into the formula: \[ z = \frac{90 - 70}{8.1} \] Calculating the numerator: \[ 90 - 70 = 20 \] Now, divide by the standard deviation: \[ z = \frac{20}{8.1} \approx 2.4691358 \] Rounding to two decimal places: \[ z \approx 2.47 \] Thus, the corresponding z-score is: \[ z = 2.47 \]

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The corresponding z-score is 2.47.
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