Vaughn Warner
06/29/2023 · Middle School

\( f(x)=2 x^{2}+16 x-10 \) (a) The function's vertex is at the point \( (-4,-42) \) (Type an ordered pair, using integers or fractions.) (b) Determine whether the parabola has a maximum value or a minimum value and find the value. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a fraction.) A. The parabola opens downward and has a maximum value of B. The parabola opens upward and has a minimum value of -42 (c) The range of \( f(x) \) is \( [-42, \infty) \) (Type your answer in interval notation. Use integers or fractions for any numbers in the expression.) (d) The function is increasing on ( \( -4, \infty) \). (Type your answer in interval notation. Use integers or fractions for any numbers in the expression.) The function is decreasing on (Type your answer in interval notation. Use integers or fractions for any numbers in the expression.)

UpStudy ThothAI Solution

Tutor-Verified Answer

Step-by-step Solution

Let's analyze the function \( f(x) = 2x^2 + 16x - 10 \). ### (a) Vertex The vertex of a parabola given by the standard form \( f(x) = ax^2 + bx + c \) can be found using the formula for the x-coordinate of the vertex: \[ x = -\frac{b}{2a} \] Here, \( a = 2 \) and \( b = 16 \): \[ x = -\frac{16}{2 \cdot 2} = -\frac{16}{4} = -4 \] To find the y-coordinate of the vertex, substitute \( x = -4 \) back into the function: \[ f(-4) = 2(-4)^2 + 16(-4) - 10 = 2(16) - 64 - 10 = 32 - 64 - 10 = -42 \] Thus, the vertex is at the point \( (-4, -42) \). ### (b) Maximum or Minimum Value Since the coefficient of \( x^2 \) (which is \( a = 2 \)) is positive, the parabola opens upward. Therefore, it has a minimum value at the vertex. The minimum value is: \[ -42 \] So the correct choice is: **B. The parabola opens upward and has a minimum value of -42.** ### (c) Range of \( f(x) \) Since the parabola opens upward and the minimum value is \( -42 \), the range of \( f(x) \) is: \[ [-42, \infty) \] ### (d) Intervals of Increase and Decrease The function is decreasing on the interval to the left of the vertex and increasing on the interval to the right of the vertex. - The function is decreasing on \( (-\infty, -4) \). - The function is increasing on \( (-4, \infty) \). ### Summary of Answers (a) Vertex: \( (-4, -42) \) (b) Minimum value: **B. The parabola opens upward and has a minimum value of -42.** (c) Range: \( [-42, \infty) \) (d) The function is increasing on \( (-4, \infty) \). The function is decreasing on \( (-\infty, -4) \).

Quick Answer

(a) Vertex: \( (-4, -42) \) (b) Minimum value: B. The parabola opens upward and has a minimum value of -42. (c) Range: \( [-42, \infty) \) (d) The function is increasing on \( (-4, \infty) \). The function is decreasing on \( (-\infty, -4) \).
Answered by UpStudy AI and reviewed by a Professional Tutor
UpStudy ThothAI
Self-Developed and Ever-Improving
Thoth AI product is constantly being upgraded and optimized.
Covers All Major Subjects
Capable of handling homework in math, chemistry, biology, physics, and more.
Instant and Accurate
Provides immediate and precise solutions and guidance.
Try Now
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text

Enter your question here…

By image
Re-Upload
Uploaded Files
xxxx.png0%
Submit
📸 STUDY CAN BE A REAL STRUGGLE
Why Not UpStudy It?
Select your plan below
Premium

You can enjoy

  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to answer and
    solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic
  • Limited Solutions