Page Marshall
08/22/2024 · Junior High School

14) \( -4 \cdot(-x+10)=(4 x+60): 2 \) 16) \( 5 x+4+3 x+4=8+4 x \)

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Vamos a resolver las ecuaciones una por una. **14)** \( -4 \cdot(-x+10)=(4 x+60): 2 \) Primero, simplificamos ambos lados de la ecuación. El lado izquierdo: \[ -4 \cdot (-x + 10) = 4x - 40 \] El lado derecho: \[ (4x + 60) : 2 = 2x + 30 \] Ahora, igualamos ambos lados: \[ 4x - 40 = 2x + 30 \] Restamos \(2x\) de ambos lados: \[ 4x - 2x - 40 = 30 \] \[ 2x - 40 = 30 \] Sumamos 40 a ambos lados: \[ 2x = 70 \] Dividimos entre 2: \[ x = 35 \] **16)** \( 5x + 4 + 3x + 4 = 8 + 4x \) Primero, combinamos términos semejantes en el lado izquierdo: \[ (5x + 3x) + (4 + 4) = 8 + 4x \] \[ 8x + 8 = 8 + 4x \] Restamos \(4x\) de ambos lados: \[ 8x - 4x + 8 = 8 \] \[ 4x + 8 = 8 \] Restamos 8 de ambos lados: \[ 4x = 0 \] Dividimos entre 4: \[ x = 0 \] **Resultados finales:** - Para la ecuación 14, \(x = 35\). - Para la ecuación 16, \(x = 0\).

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14) \(x = 35\) 16) \(x = 0\)
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