Huff Powell
01/15/2023 · Junior High School
\( \xrightarrow { Na } d \xrightarrow { \rightarrow } Na ^ { + 1 } Cl ^ { - } \)
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Step-by-step Solution
It looks like you're describing a chemical reaction involving sodium (Na) and chlorine (Cl) to form sodium chloride (NaCl). The notation you've used suggests the following:
1. \( \xrightarrow{Na} \) indicates the presence of sodium.
2. \( \xrightarrow{\rightarrow} \) suggests a reaction is taking place.
3. \( Na^{+1} \) indicates that sodium loses one electron to become a sodium ion with a +1 charge.
4. \( Cl^{-} \) indicates that chlorine gains an electron to become a chloride ion with a -1 charge.
The overall reaction can be summarized as:
\[
\text{Na} + \frac{1}{2} \text{Cl}_2 \rightarrow \text{NaCl}
\]
In this reaction, one sodium atom reacts with half a molecule of chlorine gas to produce one formula unit of sodium chloride (table salt). The sodium ion (\(Na^+\)) and the chloride ion (\(Cl^-\)) combine to form the ionic compound NaCl.
If you have any specific questions or need further clarification, feel free to ask!
Quick Answer
Sodium (Na) and chlorine (Cl) react to form sodium chloride (NaCl). Sodium loses an electron to become \(Na^+\) and chlorine gains an electron to become \(Cl^-\).
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