Evaluate the piecewise function * 2) $$ f(x)=\left\{\begin{array}{ll}x^{2} & ,-15 \leq x \leq 0 \ x-5 & , 0

Question

UpStudy AI · Accepted Answer

i) $$ f(-5) = 25 $$ ii) $$ f(15) = 10 $$ To evaluate the piecewise function $$ f(x) $$, we need to determine which part of the function to use based on the value of $$ x $$. The function is defined as follows: $$ f(x) = \begin{cases} x^{2} & \text{if } -15 \leq x \leq 0 \ x - 5 & \text{if } 0 < x \leq 15 \end{cases} $$ i) To find $$ f(-5) $$: Since $$-5$$ falls within the interval $$[-15, 0]$$, we use the first part of the piecewise function: $$ f(-5) = (-5)^{2} = 25 $$ ii) To find $$ f(15) $$: Since $$15$$ falls within the interval $$(0, 15]$$, we use the second part of the piecewise function: $$ f(15) = 15 - 5 = 10 $$ Thus, the evaluations are: i) $$ f(-5) = 25 $$ ii) $$ f(15) = 10 $$

Evaluate the piecewise function * 2) \( f(x)=\left\{\begin{array}{ll}x^{2} & ,-15 \leq x \leq 0 \\ x-5 & , 0

UpStudy ThothAI Solution

Step-by-step Solution

Quick Answer

Evaluate the piecewise function * 2) \( f(x)=\left\{\begin{array}{ll}x^{2} & ,-15 \leq x \leq 0 \\ x-5 & , 0

UpStudy ThothAI Solution

Step-by-step Solution

Quick Answer

Related Questions