$$ 1 ^ { \circ } f ( x ) = x ^ { 2 } + 2 x + 3 ; A ( 1,6 ) $$

Question

UpStudy AI · Accepted Answer

The point $$ A(1, 6) $$ lies on the curve of the function $$ f(x) = x^2 + 2x + 3 $$. It seems like you're providing a function and a point, but the notation is a bit unclear. Let's break it down: 1. The function $$ f(x) = x^2 + 2x + 3 $$ is a quadratic function. 2. The point $$ A(1, 6) $$ likely refers to a point in the Cartesian plane. To check if the point $$ A(1, 6) $$ lies on the curve defined by the function $$ f(x) $$, we can evaluate $$ f(1) $$: $$ f(1) = 1^2 + 2(1) + 3 $$ $$ = 1 + 2 + 3 $$ $$ = 6 $$ Since $$ f(1) = 6 $$, the point $$ A(1, 6) $$ does indeed lie on the curve of the function $$ f(x) $$. If you have any further questions or need additional information, feel free to ask!

\( 1 ^ { \circ } f ( x ) = x ^ { 2 } + 2 x + 3 ; A ( 1,6 ) \)

UpStudy ThothAI Solution

Step-by-step Solution

Quick Answer

\( 1 ^ { \circ } f ( x ) = x ^ { 2 } + 2 x + 3 ; A ( 1,6 ) \)

UpStudy ThothAI Solution

Step-by-step Solution

Quick Answer

Related Questions