Ross Simmons
05/02/2023 · Primary School
\begin{tabular}{c|c|}\hline Pendiente & Punto \\ \( -\frac{1}{3} \quad(-2,1) \) \\ \hline\end{tabular}
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Tutor-Verified Answer
Step-by-step Solution
Para la pendiente \( m = -\frac{1}{3} \) y el punto \( (-2, 1) \), podemos utilizar la forma punto-pendiente de la ecuación de la recta, que se expresa como:
\[
y - y_1 = m(x - x_1)
\]
donde \( (x_1, y_1) \) es el punto dado y \( m \) es la pendiente. Sustituyendo los valores:
- \( m = -\frac{1}{3} \)
- \( x_1 = -2 \)
- \( y_1 = 1 \)
La ecuación se convierte en:
\[
y - 1 = -\frac{1}{3}(x + 2)
\]
Ahora, simplificamos la ecuación:
\[
y - 1 = -\frac{1}{3}x - \frac{2}{3}
\]
Sumamos 1 a ambos lados:
\[
y = -\frac{1}{3}x - \frac{2}{3} + 1
\]
Convertimos 1 a tercios:
\[
y = -\frac{1}{3}x - \frac{2}{3} + \frac{3}{3}
\]
Esto nos da:
\[
y = -\frac{1}{3}x + \frac{1}{3}
\]
Por lo tanto, la ecuación de la recta con pendiente \( -\frac{1}{3} \) que pasa por el punto \( (-2, 1) \) es:
\[
y = -\frac{1}{3}x + \frac{1}{3}
\]
Quick Answer
La ecuación de la recta es \( y = -\frac{1}{3}x + \frac{1}{3} \).
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