Lang Reid
02/28/2023 · Junior High School

Let \( f(x)=7+\sqrt{6 x-5} \). Find \( f^{-1}(x) \) \( f^{-1}(x)=\square \)

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To find the inverse function \( f^{-1}(x) \) of the function \( f(x) = 7 + \sqrt{6x - 5} \), we will follow these steps: 1. **Set \( f(x) \) equal to \( y \)**: \[ y = 7 + \sqrt{6x - 5} \] 2. **Solve for \( x \) in terms of \( y \)**: - First, isolate the square root: \[ y - 7 = \sqrt{6x - 5} \] - Next, square both sides to eliminate the square root: \[ (y - 7)^2 = 6x - 5 \] - Rearranging gives: \[ 6x = (y - 7)^2 + 5 \] - Now, solve for \( x \): \[ x = \frac{(y - 7)^2 + 5}{6} \] 3. **Replace \( y \) with \( x \) to express the inverse function**: \[ f^{-1}(x) = \frac{(x - 7)^2 + 5}{6} \] Thus, the inverse function is: \[ \boxed{f^{-1}(x) = \frac{(x - 7)^2 + 5}{6}} \]

Quick Answer

\( f^{-1}(x) = \frac{(x - 7)^2 + 5}{6} \)
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