O'Quinn Schultz
02/26/2024 · High School
6) \( \lim _{x \rightarrow 7} \frac{x-7}{x^{2}-49}= \)
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Tutor-Verified Answer
Step-by-step Solution
Para resolver el límite \( \lim _{x \rightarrow 7} \frac{x-7}{x^{2}-49} \), primero observamos que al sustituir \( x = 7 \) tanto el numerador como el denominador se vuelven cero, lo que nos da una forma indeterminada \( \frac{0}{0} \).
Podemos simplificar la expresión. Notamos que el denominador \( x^2 - 49 \) se puede factorizar:
\[
x^2 - 49 = (x - 7)(x + 7)
\]
Entonces, la expresión original se convierte en:
\[
\frac{x-7}{x^2 - 49} = \frac{x-7}{(x-7)(x+7)}
\]
Siempre que \( x \neq 7 \), podemos cancelar \( x - 7 \) en el numerador y el denominador:
\[
\frac{1}{x + 7}
\]
Ahora podemos calcular el límite:
\[
\lim _{x \rightarrow 7} \frac{1}{x + 7} = \frac{1}{7 + 7} = \frac{1}{14}
\]
Por lo tanto, el resultado del límite es:
\[
\lim _{x \rightarrow 7} \frac{x-7}{x^{2}-49} = \frac{1}{14}
\]
Quick Answer
El límite es \( \frac{1}{14} \).
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