\begin{tabular}{l|l} 1) \( 7,8+3 \frac{5}{8}-2,8-3 \frac{3}{8} \) & 1) \( 9 \cdot 157+9 \cdot 143 \) \\ 2) \( 4 \frac{3}{8}-3 \frac{3}{7}-9,5+5 \frac{1}{8} \) & 2) \( 3,5 \cdot 2,4-3,5 \cdot 1,4 \) \\ 3) \( -2 \cdot(-50) \cdot 6 \cdot 12 \) & 3) \( 4,75 \cdot 3,2-3,2 \cdot 3,25 \) \\ 4) \( 11 \cdot(-4) \cdot(-7) \cdot 25 \) & 4) \( \frac{4}{5} \cdot \frac{2}{3}+\frac{2}{3} \cdot \frac{2}{5} \) \\ 5) \( -\frac{2}{3} \cdot\left(-\frac{5}{14}\right) \cdot\left(-\frac{3}{8}\right) \cdot \frac{7}{5} \) & 5) \( 1 \frac{1}{3} \cdot \frac{5}{14}-1 \frac{1}{3} \cdot \frac{1}{7} \) \\ 6) \( -3 \frac{1}{3} \cdot\left(-1 \frac{2}{7}\right) \cdot(-3) \cdot(-7) \) & 6) \( 12,9 \cdot \frac{3}{8}-11,3 \cdot \frac{3}{8} \) \\ 7) \( 8,757-7,8+1,043 \) & 7) \( 1 \frac{1}{19} \cdot \frac{3}{4}-\frac{1}{19} \cdot \frac{3}{4} \) \\ 8) \( \frac{3}{8}-\frac{3}{4}+\frac{1}{8} \) & 8) \( 2 \frac{3}{8} \cdot 4 \frac{4}{7}-2 \frac{1}{8} \cdot 4 \frac{4}{7} \) \\ 9) \( \frac{2}{3}+0,4-\frac{2}{3}+0,6 \) & 9) \( \left(\frac{3}{11}+\frac{2}{7}\right): \frac{2}{11} \) \\ 10) \( -\frac{2}{3} \cdot \frac{4}{7} \cdot 1 \frac{1}{2} \) & 10) \( \left(\frac{2}{5}+\frac{3}{10}\right): \frac{11}{20} \) \\ 12) \( -2,77+7 \frac{5}{9}-0,23+4 \frac{7}{9} \) & 11) \( \left(\frac{6}{11}-\frac{7}{15}\right): \frac{3}{5} \) \\ 13) \( 4 \frac{1}{2}+2 \frac{1}{6}-5 \frac{5}{9}-3 \frac{1}{3}-2 \frac{1}{9} \) & 13) \( 12 \cdot\left(\frac{5}{12}+\frac{3}{4}\right) \) \\ 14) \( -0,2 \cdot 0,8 \cdot(-5) \cdot(-1,25) \) & 14) \( \left(\frac{3}{5}-\frac{2}{15}\right) \cdot 15 \)\end{tabular}

Конечно! Вот решения для каждой из задач: ### Задачи 1-14 1) \( 7,8 + 3 \frac{5}{8} - 2,8 - 3 \frac{3}{8} \) \( = 7,8 + 3,625 - 2,8 - 3,375 = 5,25 \) \( 9 \cdot 157 + 9 \cdot 143 = 9 \cdot (157 + 143) = 9 \cdot 300 = 2700 \) 2) \( 4 \frac{3}{8} - 3 \frac{3}{7} - 9,5 + 5 \frac{1}{8} \) \( = 4,375 - 3,42857 - 9,5 + 5,125 = -3,42857 \) \( 3,5 \cdot 2,4 - 3,5 \cdot 1,4 = 3,5 \cdot (2,4 - 1,4) = 3,5 \cdot 1 = 3,5 \) 3) \( -2 \cdot (-50) \cdot 6 \cdot 12 = 14400 \) \( 4,75 \cdot 3,2 - 3,2 \cdot 3,25 = 3,2 \cdot (4,75 - 3,25) = 3,2 \cdot 1,5 = 4,8 \) 4) \( 11 \cdot (-4) \cdot (-7) \cdot 25 = 7700 \) \( \frac{4}{5} \cdot \frac{2}{3} + \frac{2}{3} \cdot \frac{2}{5} = \frac{2}{3} \cdot \left(\frac{4}{5} + \frac{2}{5}\right) = \frac{2}{3} \cdot \frac{6}{5} = \frac{12}{15} = \frac{4}{5} \) 5) \( -\frac{2}{3} \cdot \left(-\frac{5}{14}\right) \cdot \left(-\frac{3}{8}\right) \cdot \frac{7}{5} = -\frac{2}{3} \cdot \frac{3}{8} = -\frac{1}{4} \) \( 1 \frac{1}{3} \cdot \frac{5}{14} - 1 \frac{1}{3} \cdot \frac{1}{7} = \frac{4}{3} \cdot \frac{5}{14} - \frac{4}{3} \cdot \frac{1}{7} = \frac{4}{3} \cdot \left(\frac{5}{14} - \frac{2}{14}\right) = \frac{4}{3} \cdot \frac{3}{14} = \frac{1}{14} \) 6) \( -3 \frac{1}{3} \cdot \left(-1 \frac{2}{7}\right) \cdot (-3) \cdot (-7) = 3 \cdot \frac{9}{7} \cdot 3 \cdot 7 = 81 \) \( 12,9 \cdot \frac{3}{8} - 11,3 \cdot \frac{3}{8} = (12,9 - 11,3) \cdot \frac{3}{8} = 1,6 \cdot \frac{3}{8} = 0,6 \) 7) \( 8,757 - 7,8 + 1,043 = 1 \) \( 1 \frac{1}{19} \cdot \frac{3}{4} - \frac{1}{19} \cdot \frac{3}{4} = 0 \) 8) \( \frac{3}{8} - \frac{3}{4} + \frac{1}{8} = \frac{3}{8} - \frac{6}{8} + \frac{1}{8} = -\frac{2}{8} = -\frac{1}{4} \) \( 2 \frac{3}{8} \cdot 4 \frac{4}{7} - 2 \frac{1}{8} \cdot 4 \frac{4}{7} = 4 \frac{1}{8} \cdot 4 \frac{4}{7} = 16 \cdot \frac{4}{7} = \frac{64}{7} \) 9) \( \frac{2}{3} + 0,4 - \frac{2}{3} + 0,6 = 1 \) \( \left(\frac{3}{11} + \frac{2}{7}\right) : \frac{2}{11} = \frac{3 \cdot 7 + 2 \cdot 11}{11 \cdot 7} \cdot \frac{11}{2} = \frac{21 + 22}{77} \cdot \frac{11}{2} = \frac{43}{77} \cdot \frac{11}{2} = \frac{473}{154} \) 10) \( -\frac{2}{3} \cdot \frac{4}{7} \cdot 1 \frac{1}{2} = -\frac{2}{3} \cdot \frac{4}{7} \cdot \frac{3}{2} = -\frac{4}{7} \) \( \left(\frac{2}{5} + \frac{3}{10}\right) : \frac{11}{20} = \frac{4}{10} : \frac{11}{20} = \frac{4}{10} \cdot \frac{20}{11} = \frac{8}{11} \) 12) \( -2,77 + 7 \frac{5}{9} - 0,23 + 4 \frac{7}{9} = 9 \) \( \left(\frac{6}{11} - \frac{7}{15}\right) : \frac{3}{5} = \frac{90 - 77}{165} \cdot \frac{5}{3} = \frac{13}{165} \cdot \frac{5}{3} = \frac{65}{495} \) 13) \( 4 \frac{1}{2} + 2 \frac{1}{6} - 5 \frac{5}{9} - 3 \frac{1}{3} - 2 \frac{1}{9} = -4 \) \( 12 \cdot \left(\frac{5}{12} + \frac{3}{4}\right) = 12 \cdot \left(\frac{5}{12} + \frac{9}{12}\right) = 12 \cdot \frac{14}{12} = 14 \) 14) \( -0,2 \cdot 0,8 \cdot (-5) \cdot (-1,25) = 1 \) \( \left(\frac{3}{5} - \frac{2}{15}\right) \cdot 15 = \frac{9}{15} \cdot 15 = 9 \) Если у вас есть дополнительные вопросы или нужна помощь с другими задачами, дайте знать!