Evaluate the following. Assume that all bases are not equal to 0 . $$ (6 x+3)^{0} $$

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$$(6x + 3)^{0} = 1$$ To evaluate the expression $$(6x + 3)^{0}$$, we can use the property of exponents that states any non-zero number raised to the power of 0 is equal to 1. Since $$6x + 3$$ is not equal to 0 (as long as $$x$$ is not equal to $$-\frac{1}{2}$$), we can conclude that: $$ (6x + 3)^{0} = 1 $$ Thus, the final answer is: $$ \boxed{1} $$

Evaluate the following. Assume that all bases are not equal to 0 . \[ (6 x+3)^{0} \]

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Evaluate the following. Assume that all bases are not equal to 0 . \[ (6 x+3)^{0} \]

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