Lyons Delgado
01/10/2023 · Primary School

Convertin a Metro' Cado und de bi Sguinstes merom \( \begin{array}{ll}\text { a) } 42.3 \mathrm{~cm} & \text { b) } 62 \mathrm{dm} \text { a) } 12 \mathrm{~km} \\ \text { d) } 0.023 \mathrm{~m} & \text { e) } 570 \mathrm{um}\end{array} \)

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To convert the given measurements into meters, we can use the following conversion factors: - \(1 \text{ cm} = 0.01 \text{ m}\) - \(1 \text{ dm} = 0.1 \text{ m}\) - \(1 \text{ km} = 1000 \text{ m}\) - \(1 \text{ m} = 1000 \text{ mm}\) - \(1 \text{ um} = 1 \times 10^{-6} \text{ m}\) Now, let's convert each measurement: a) \(42.3 \text{ cm}\): \[ 42.3 \text{ cm} \times 0.01 \text{ m/cm} = 0.423 \text{ m} \] b) \(62 \text{ dm}\): \[ 62 \text{ dm} \times 0.1 \text{ m/dm} = 6.2 \text{ m} \] c) \(12 \text{ km}\): \[ 12 \text{ km} \times 1000 \text{ m/km} = 12000 \text{ m} \] d) \(0.023 \text{ m}\): \[ 0.023 \text{ m} \text{ (already in meters)} \] e) \(570 \text{ um}\): \[ 570 \text{ um} \times 1 \times 10^{-6} \text{ m/um} = 0.000570 \text{ m} = 5.7 \times 10^{-4} \text{ m} \] Now, summarizing the conversions: \[ \begin{array}{ll} \text{a) } 0.423 \text{ m} & \text{b) } 6.2 \text{ m} \\ \text{c) } 12000 \text{ m} & \text{d) } 0.023 \text{ m} \\ \text{e) } 5.7 \times 10^{-4} \text{ m} \\ \end{array} \]

Quick Answer

\[ \begin{array}{ll} \text{a) } 0.423 \text{ m} & \text{b) } 6.2 \text{ m} \\ \text{c) } 12000 \text{ m} & \text{d) } 0.023 \text{ m} \\ \text{e) } 5.7 \times 10^{-4} \text{ m} \\ \end{array} \]
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