Reed Hilton
01/02/2024 · Elementary School

\( = 3 _ { 3 } ^ { 1 } ( 3 - 2 x ) = 10 ( x - \frac { 1 } { 2 } ) \)

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To solve the equation \[ 3_{3}^{1} (3 - 2x) = 10 \left( x - \frac{1}{2} \right), \] we first need to clarify the notation. The notation \(3_{3}^{1}\) is not standard in mathematics. If we assume it means simply \(3\), we can rewrite the equation as: \[ 3(3 - 2x) = 10 \left( x - \frac{1}{2} \right). \] Now, let's simplify both sides of the equation. Starting with the left side: \[ 3(3 - 2x) = 9 - 6x. \] Now, simplifying the right side: \[ 10 \left( x - \frac{1}{2} \right) = 10x - 5. \] Now we have the equation: \[ 9 - 6x = 10x - 5. \] Next, we will move all terms involving \(x\) to one side and constant terms to the other side. Adding \(6x\) to both sides gives: \[ 9 = 16x - 5. \] Now, add \(5\) to both sides: \[ 14 = 16x. \] Now, divide both sides by \(16\): \[ x = \frac{14}{16} = \frac{7}{8}. \] Thus, the solution to the equation is: \[ \boxed{\frac{7}{8}}. \]

Quick Answer

The solution to the equation is \( x = \frac{7}{8} \).
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