Floyd Wells
03/11/2023 · Primary School
\( \begin{array}{l}\text { Evacion } \\ y=2 x-3\end{array} \) \( \begin{array}{r}0.41 \\ y=-3 x+7\end{array} \) \( \begin{array}{rr}y & +5\end{array} \)
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Step-by-step Solution
It looks like you have provided two equations of lines and possibly a point or a value. Let's clarify the equations and see if you want to find their intersection or perform some other operation.
The equations you provided are:
1. \( y = 2x - 3 \)
2. \( y = -3x + 7 \)
To find the intersection of these two lines, we can set them equal to each other:
\[
2x - 3 = -3x + 7
\]
Now, let's solve for \( x \):
1. Add \( 3x \) to both sides:
\[
2x + 3x - 3 = 7
\]
\[
5x - 3 = 7
\]
2. Add \( 3 \) to both sides:
\[
5x = 10
\]
3. Divide by \( 5 \):
\[
x = 2
\]
Now, substitute \( x = 2 \) back into one of the original equations to find \( y \). We'll use the first equation:
\[
y = 2(2) - 3 = 4 - 3 = 1
\]
So, the intersection point of the two lines is \( (2, 1) \).
If you have any other specific questions or need further assistance, please let me know!
Quick Answer
The intersection point of the lines \( y = 2x - 3 \) and \( y = -3x + 7 \) is \( (2, 1) \).
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