Bowman Moran
05/21/2023 · High School

b) Completando el cuadrado. \( 3 x^{2}-6 x-5=0 \)

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Para completar el cuadrado en la ecuación \( 3x^2 - 6x - 5 = 0 \), seguimos estos pasos: 1. **Factorizar el coeficiente de \( x^2 \)**: Primero, sacamos el factor común de 3 de los términos que contienen \( x \): \[ 3(x^2 - 2x) - 5 = 0 \] 2. **Mover el término constante al otro lado**: \[ 3(x^2 - 2x) = 5 \] 3. **Completar el cuadrado**: Para completar el cuadrado dentro del paréntesis, tomamos el coeficiente de \( x \) (que es -2), lo dividimos por 2 y lo elevamos al cuadrado: \[ \left(-\frac{2}{2}\right)^2 = 1 \] Ahora, sumamos y restamos 1 dentro del paréntesis: \[ 3(x^2 - 2x + 1 - 1) = 5 \] Esto se puede reescribir como: \[ 3((x - 1)^2 - 1) = 5 \] 4. **Simplificar**: \[ 3(x - 1)^2 - 3 = 5 \] Sumamos 3 a ambos lados: \[ 3(x - 1)^2 = 8 \] 5. **Dividir por 3**: \[ (x - 1)^2 = \frac{8}{3} \] 6. **Tomar la raíz cuadrada**: \[ x - 1 = \pm \sqrt{\frac{8}{3}} \] Simplificando la raíz: \[ x - 1 = \pm \frac{2\sqrt{2}}{\sqrt{3}} = \pm \frac{2\sqrt{6}}{3} \] 7. **Despejar \( x \)**: \[ x = 1 \pm \frac{2\sqrt{6}}{3} \] Por lo tanto, las soluciones de la ecuación \( 3x^2 - 6x - 5 = 0 \) son: \[ x = 1 + \frac{2\sqrt{6}}{3} \quad \text{y} \quad x = 1 - \frac{2\sqrt{6}}{3} \]

Quick Answer

Las soluciones de la ecuación \( 3x^2 - 6x - 5 = 0 \) son \( x = 1 + \frac{2\sqrt{6}}{3} \) y \( x = 1 - \frac{2\sqrt{6}}{3} \).
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