Li Hills
06/11/2023 · Middle School
Find the matrix associated with the rotations (a) \( \pi / 2 \) (b) \( \pi / 4 \) (c) \( \pi / 6 \).
UpStudy ThothAI Solution
Tutor-Verified Answer
Step-by-step Solution
To find the rotation matrices associated with the angles \( \pi/2 \), \( \pi/4 \), and \( \pi/6 \), we can use the standard rotation matrix formula for a counterclockwise rotation by an angle \( \theta \):
\[
R(\theta) = \begin{pmatrix}
\cos(\theta) & -\sin(\theta) \\
\sin(\theta) & \cos(\theta)
\end{pmatrix}
\]
Now, we will compute the rotation matrices for each specified angle.
### (a) Rotation by \( \pi/2 \)
For \( \theta = \pi/2 \):
\[
R\left(\frac{\pi}{2}\right) = \begin{pmatrix}
\cos\left(\frac{\pi}{2}\right) & -\sin\left(\frac{\pi}{2}\right) \\
\sin\left(\frac{\pi}{2}\right) & \cos\left(\frac{\pi}{2}\right)
\end{pmatrix} = \begin{pmatrix}
0 & -1 \\
1 & 0
\end{pmatrix}
\]
### (b) Rotation by \( \pi/4 \)
For \( \theta = \pi/4 \):
\[
R\left(\frac{\pi}{4}\right) = \begin{pmatrix}
\cos\left(\frac{\pi}{4}\right) & -\sin\left(\frac{\pi}{4}\right) \\
\sin\left(\frac{\pi}{4}\right) & \cos\left(\frac{\pi}{4}\right)
\end{pmatrix} = \begin{pmatrix}
\frac{\sqrt{2}}{2} & -\frac{\sqrt{2}}{2} \\
\frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2}
\end{pmatrix}
\]
### (c) Rotation by \( \pi/6 \)
For \( \theta = \pi/6 \):
\[
R\left(\frac{\pi}{6}\right) = \begin{pmatrix}
\cos\left(\frac{\pi}{6}\right) & -\sin\left(\frac{\pi}{6}\right) \\
\sin\left(\frac{\pi}{6}\right) & \cos\left(\frac{\pi}{6}\right)
\end{pmatrix} = \begin{pmatrix}
\frac{\sqrt{3}}{2} & -\frac{1}{2} \\
\frac{1}{2} & \frac{\sqrt{3}}{2}
\end{pmatrix}
\]
### Summary of Rotation Matrices
- For \( \pi/2 \):
\[
R\left(\frac{\pi}{2}\right) = \begin{pmatrix}
0 & -1 \\
1 & 0
\end{pmatrix}
\]
- For \( \pi/4 \):
\[
R\left(\frac{\pi}{4}\right) = \begin{pmatrix}
\frac{\sqrt{2}}{2} & -\frac{\sqrt{2}}{2} \\
\frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2}
\end{pmatrix}
\]
- For \( \pi/6 \):
\[
R\left(\frac{\pi}{6}\right) = \begin{pmatrix}
\frac{\sqrt{3}}{2} & -\frac{1}{2} \\
\frac{1}{2} & \frac{\sqrt{3}}{2}
\end{pmatrix}
\]
Quick Answer
- For \( \pi/2 \):
\[
R\left(\frac{\pi}{2}\right) = \begin{pmatrix}
0 & -1 \\
1 & 0
\end{pmatrix}
\]
- For \( \pi/4 \):
\[
R\left(\frac{\pi}{4}\right) = \begin{pmatrix}
\frac{\sqrt{2}}{2} & -\frac{\sqrt{2}}{2} \\
\frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2}
\end{pmatrix}
\]
- For \( \pi/6 \):
\[
R\left(\frac{\pi}{6}\right) = \begin{pmatrix}
\frac{\sqrt{3}}{2} & -\frac{1}{2} \\
\frac{1}{2} & \frac{\sqrt{3}}{2}
\end{pmatrix}
\]
Answered by UpStudy AI and reviewed by a Professional Tutor
UpStudy ThothAI
Self-Developed and Ever-Improving
Thoth AI product is constantly being upgraded and optimized.
Covers All Major Subjects
Capable of handling homework in math, chemistry, biology, physics, and more.
Instant and Accurate
Provides immediate and precise solutions and guidance.
Try Now
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text
Enter your question here…
By image
Re-Upload
Submit