Finance, growth and decay Revistow A species of extremely rare shark has a very long lifespan and seldom has children. If there are a total of 3970 this type of shark and the population's growth rate is \( 9 \% \) each year, determine how many sharks there will be in? 9years. mstrucrion: Round your answer to the nearest whole number.

Given: - Initial population of the shark species: 3970 - Growth rate: 9% per year To determine the population of sharks after 9 years, we can use the formula for exponential growth: \[ P = P_0 \times (1 + r)^n \] Where: - \( P \) is the final population - \( P_0 \) is the initial population - \( r \) is the growth rate per year - \( n \) is the number of years Substitute the given values into the formula: \[ P = 3970 \times (1 + 0.09)^9 \] Now, we can calculate the final population of sharks after 9 years. Calculate the value by following steps: - step0: Calculate: \(3970\left(1+0.09\right)^{9}\) - step1: Add the numbers: \(3970\times 1.09^{9}\) - step2: Convert the expressions: \(3970\left(\frac{109}{100}\right)^{9}\) - step3: Simplify: \(3970\times \frac{109^{9}}{100^{9}}\) - step4: Rewrite the expression: \(10\times 397\times \frac{109^{9}}{100^{9}}\) - step5: Rewrite the expression: \(10\times 397\times \frac{109^{9}}{10^{18}}\) - step6: Reduce the numbers: \(397\times \frac{109^{9}}{10^{17}}\) - step7: Multiply: \(\frac{397\times 109^{9}}{10^{17}}\) The population of sharks after 9 years will be approximately 8622. The answer is rounded to the nearest whole number.